4t^2+t=95

Solution for 4t^2+t=95 equation:

4t^2+t=95

We move all terms to the left:

4t^2+t-(95)=0

a = 4; b = 1; c = -95;
Δ = b2-4ac
Δ = 12-4·4·(-95)
Δ = 1521
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1521}=39$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-39}{2*4}=\frac{-40}{8}
=-5
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+39}{2*4}=\frac{38}{8}
=4+3/4
$